Канал: MathsSmart

Fold square paper to triangular pyramid | Find height of the pyramid | Paper folding puzzle

Fold square paper to triangular pyramid | Find height of the pyramid | Paper folding puzzle

Two squares in a semi-circle Find area of squares, diameter is 10 units PRMO RMO NTSE INMO IIT-JEE

Two squares in a semi-circle Find area of squares, diameter is 10 units PRMO RMO NTSE INMO IIT-JEE

Find area of one triangle | One simple trick to avoid unnecessary calculations | PRMO RMO NMTC

Find area of one triangle | One simple trick to avoid unnecessary calculations | PRMO RMO NMTC

World's Hardest "Chess" Puzzle | How to place 4 Queens and 1 Bishop to cover the entire chess board

World's Hardest "Chess" Puzzle | How to place 4 Queens and 1 Bishop to cover the entire chess board

World's hardest "Chess puzzle" | Fun Puzzles | Chess piece placement puzzle

World's hardest "Chess puzzle" | Fun Puzzles | Chess piece placement puzzle

Interesting Square Problem | Intersecting diagonals and angle bisector | PRMO RMO INMO NMTC NTSE |

Interesting Square Problem | Intersecting diagonals and angle bisector | PRMO RMO INMO NMTC NTSE |

Solution to world's hardest Paper puzzle | Fum Math | Math puzzle | Math Quiz

Solution to world's hardest Paper puzzle | Fum Math | Math puzzle | Math Quiz

World's hardest Paper puzzle | Fum Math | Math puzzle | Math Quiz

World's hardest Paper puzzle | Fum Math | Math puzzle | Math Quiz

Menelaus theorem : Proof and derivation | Transversal cutting a triangle | PRMO RMO INMO IMO | NMTC

Menelaus theorem : Proof and derivation | Transversal cutting a triangle | PRMO RMO INMO IMO | NMTC

Stewarts theorem: Three Collinear points, Proof & derivation, Geometry Straight lines & triangles

Stewarts theorem: Three Collinear points, Proof & derivation, Geometry Straight lines & triangles

World's hardest Boating puzzle from the book "World's hardest puzzles" | Competitive Exams

World's hardest Boating puzzle from the book "World's hardest puzzles" | Competitive Exams

Very hard problem | Count all triangles | Total Number of triangles | PRMO RMO INMO IMO NMTC NTSE

Very hard problem | Count all triangles | Total Number of triangles | PRMO RMO INMO IMO NMTC NTSE

Very Interesting Problem | Square Number in a triangle | Triangles in a triangle | PRMO RMO

Very Interesting Problem | Square Number in a triangle | Triangles in a triangle | PRMO RMO

Find Area of the shaded region | Square on Median | Medium Hard | PRMO RMO INMO NMTC NTSE IBPS

Find Area of the shaded region | Square on Median | Medium Hard | PRMO RMO INMO NMTC NTSE IBPS

Derivation : Formula to find the length of a median of a triangle ma=(1/2) sqrt(2b^2+2c^2-a^2)

Derivation : Formula to find the length of a median of a triangle ma=(1/2) sqrt(2b^2+2c^2-a^2)

See and solve Easy | Find area of total figure | Ratio of areas in similar triangles PRMO NMTC NTSE

See and solve Easy | Find area of total figure | Ratio of areas in similar triangles PRMO NMTC NTSE

How to find the total number of factors of any given number | Derivation PRMO RMO NTSE Number theory

How to find the total number of factors of any given number | Derivation PRMO RMO NTSE Number theory

Problem with inverse of roots of a cubic equation PRMO RMO JEE INMO NTSE | HARD | Roots of equation

Problem with inverse of roots of a cubic equation PRMO RMO JEE INMO NTSE | HARD | Roots of equation

Hard Geometry Problem Find Length of perpendicular, where area of ABCD = 24 | PRMO RMO INMO SSB IMO

Hard Geometry Problem Find Length of perpendicular, where area of ABCD = 24 | PRMO RMO INMO SSB IMO

Interesting String puzzle | Folded string puzzle | PRMO RMO INMO SSB IBPS NTSE IMO

Interesting String puzzle | Folded string puzzle | PRMO RMO INMO SSB IBPS NTSE IMO

Example using Ceva's theorem | A problem which became very easy after using Ceva's theorem

Example using Ceva's theorem | A problem which became very easy after using Ceva's theorem

Proof of Ceva's theorem | PRMO RMO INMO IMO SSB NTSE

Proof of Ceva's theorem | PRMO RMO INMO IMO SSB NTSE

Find area of the quarter circle whose radius is not given | Hard | PRMO RMO INMO SSB IBPS

Find area of the quarter circle whose radius is not given | Hard | PRMO RMO INMO SSB IBPS

A folded paper puzzle | Folded Rectangle Puzzle | PRMO RMO INMO SSB IBPS

A folded paper puzzle | Folded Rectangle Puzzle | PRMO RMO INMO SSB IBPS

Finding roots of a complicated looking expression | Solve for x | PRMO RMO SSB IBPS

Finding roots of a complicated looking expression | Solve for x | PRMO RMO SSB IBPS

Four circles tangent to each other in a Hexagon Find area of two smallest circles PRMO RMO IMO INMO

Four circles tangent to each other in a Hexagon Find area of two smallest circles PRMO RMO IMO INMO

Area of small convex hexagon made by two overlapping triangles Hard Problem and Simple solution PRMO

Area of small convex hexagon made by two overlapping triangles Hard Problem and Simple solution PRMO

Two ways of solving an interesting problem | Find Radius of the circle | PRMO RMO INMO SSB

Two ways of solving an interesting problem | Find Radius of the circle | PRMO RMO INMO SSB

Circles | Area of shaded region | Solution without touching a pen | A very short fun video | PRMO

Circles | Area of shaded region | Solution without touching a pen | A very short fun video | PRMO

Find length of the chord, two other chords are given | PRMO RMO SSB INMO

Find length of the chord, two other chords are given | PRMO RMO SSB INMO

A fun Puzzle for this tough time (COVID 19) | Stay home Stay safe | Enjoy solving

A fun Puzzle for this tough time (COVID 19) | Stay home Stay safe | Enjoy solving

Finding Angle | A very difficult problem with easy solution | PRMO RMO INMO SSB SSC IMO Geometry

Finding Angle | A very difficult problem with easy solution | PRMO RMO INMO SSB SSC IMO Geometry

Find radius of the circle when two intersecting chords are given RMO INMO PRMO SSB IMO IBPS

Find radius of the circle when two intersecting chords are given RMO INMO PRMO SSB IMO IBPS

Extremely hard problem made easy | Two squares shaded region | PRMO RMO INMO IMO SSB

Extremely hard problem made easy | Two squares shaded region | PRMO RMO INMO IMO SSB

Find Angle of a triangle in a square A difficult problem with interesting solution PRMO RMO INMO IMO

Find Angle of a triangle in a square A difficult problem with interesting solution PRMO RMO INMO IMO

Derivation of formula to find the Radius of the circumcircle | Why and How | PRMO RMO INMO IMO

Derivation of formula to find the Radius of the circumcircle | Why and How | PRMO RMO INMO IMO

Four squares in circle area Find the area of the circle

Four squares in circle area Find the area of the circle

Hard Problem | Find Angle x | PRMO RMO INMO IMO Math Olympiads SSC

Hard Problem | Find Angle x | PRMO RMO INMO IMO Math Olympiads SSC

Find the sides of the pentagon made by joining points of 5-pointed star | RMO INMO IMO SSC

Find the sides of the pentagon made by joining points of 5-pointed star | RMO INMO IMO SSC

Scary problem & a simple solution, Number of perfect squares can using 20 0s, 20 1s, 20 2s & 20 3s.

Scary problem & a simple solution, Number of perfect squares can using 20 0s, 20 1s, 20 2s & 20 3s.

Area of moon shaped portions of the circles | Tricky problem | Simple Solution PRMO RMO IMO

Area of moon shaped portions of the circles | Tricky problem | Simple Solution PRMO RMO IMO

Hardest Problem ever | Find the Area of the biggest Square | Easy Solution | PRMO RMO IMO SSC

Hardest Problem ever | Find the Area of the biggest Square | Easy Solution | PRMO RMO IMO SSC

Most popular WhatsApp puzzle during Covid 19 lockdown | Area of the square inside another square

Most popular WhatsApp puzzle during Covid 19 lockdown | Area of the square inside another square

PRMO 2015-16 Tricky problem for High School O is a random point in ABC find OD/AD + OE/BE + OF/CF

PRMO 2015-16 Tricky problem for High School O is a random point in ABC find OD/AD + OE/BE + OF/CF

A semicircle and a tangent inscribed in a square Ratio of areas of shaded region and unshaded region

A semicircle and a tangent inscribed in a square Ratio of areas of shaded region and unshaded region

Very difficult challenging problem Find length of chord PQ, circle inscribed in a rectangle PRMO RMO

Very difficult challenging problem Find length of chord PQ, circle inscribed in a rectangle PRMO RMO

Remainders not same, Difference not same, Find x, divided by 13,15, 19 give remainders 1,2,3

Remainders not same, Difference not same, Find x, divided by 13,15, 19 give remainders 1,2,3

Find the area of the shaded region | Mensuration | PRMO NMTC Mental Ability | Trapezoid | IBPS Bank

Find the area of the shaded region | Mensuration | PRMO NMTC Mental Ability | Trapezoid | IBPS Bank

What ratio is shaded ? Four equilateral triangles inscribed in a rectangle PRMO RMO IBPS IMO Mental

What ratio is shaded ? Four equilateral triangles inscribed in a rectangle PRMO RMO IBPS IMO Mental

Find the sum of the digits of a long sequence, last term is 321 digit long 9+99+999 + ...(321 terms)

Find the sum of the digits of a long sequence, last term is 321 digit long 9+99+999 + ...(321 terms)

Extremely hard geometry problem | Find radius of the smallest circle Three circles RMO IMO INMO SSB

Extremely hard geometry problem | Find radius of the smallest circle Three circles RMO IMO INMO SSB

Find remainder of [(257)^33 + 46]^26 / 50 a very hard problem solved using Number Theory

Find remainder of [(257)^33 + 46]^26 / 50 a very hard problem solved using Number Theory

Hard problem in mensuration | Area of the shaded region | PRMO | RMO | Mental ability

Hard problem in mensuration | Area of the shaded region | PRMO | RMO | Mental ability

How to find Equation of parallel and Perpendicular lines to a given line y = mx + c

How to find Equation of parallel and Perpendicular lines to a given line y = mx + c

Shortcut to remember values and conversions of trigonometric ratios (T-ratios) in different quadrant

Shortcut to remember values and conversions of trigonometric ratios (T-ratios) in different quadrant

How and why | different equations of lines | y = mx + c, line passing through one and two points

How and why | different equations of lines | y = mx + c, line passing through one and two points

How and why T Rstios, Tan(90-A) Tan(90+A) Tan180-A tan 180+A tan 270-A tan 270+A tan 360-A cot 270-A

How and why T Rstios, Tan(90-A) Tan(90+A) Tan180-A tan 180+A tan 270-A tan 270+A tan 360-A cot 270-A

Sin(90-A), Sin(90+A), Cos(180-A), Cos(180+A), Sin(270-A), Sin(270+A),Cos(360-A) How Why Trigonometry

Sin(90-A), Sin(90+A), Cos(180-A), Cos(180+A), Sin(270-A), Sin(270+A),Cos(360-A) How Why Trigonometry

A tricky problem in rectangles | Olympiads, Bank PO, IBPS, PRMO NMTC IMO

A tricky problem in rectangles | Olympiads, Bank PO, IBPS, PRMO NMTC IMO

Very Very Tricky problem | Next Perihelion together | HARD RMO, PRMO, NMTC, Mental Ability, Olympiad

Very Very Tricky problem | Next Perihelion together | HARD RMO, PRMO, NMTC, Mental Ability, Olympiad

Probability | 99 fair dice and 1 faulty die, Find the probability of sum divisible by 6 Hard problem

Probability | 99 fair dice and 1 faulty die, Find the probability of sum divisible by 6 Hard problem

Area Square inscribed in between 4 identical or congruent circles | NMTC | PRMO | RMO Mental Ability

Area Square inscribed in between 4 identical or congruent circles | NMTC | PRMO | RMO Mental Ability

Number Theory Find Last three Digits 2005^11 + 2005^12 + ... + 2005^2006 NMTC PRMO SSC IBPS Bank PO

Number Theory Find Last three Digits 2005^11 + 2005^12 + ... + 2005^2006 NMTC PRMO SSC IBPS Bank PO

Hard problem on Perimeter of a rectangle, NO SIDE GIVEN, How to find lengths PRMO RMP NMTC Olympiad

Hard problem on Perimeter of a rectangle, NO SIDE GIVEN, How to find lengths PRMO RMP NMTC Olympiad

What will be the last digit 1032 ^ 1032 | Hard problem with easy solution

What will be the last digit 1032 ^ 1032 | Hard problem with easy solution

Find 250 th term of the sequence 1,2, 2, 3, 3, 3, 4, 4, 4, 4, ... Number Pattern & Puzzle NMTC PRMO

Find 250 th term of the sequence 1,2, 2, 3, 3, 3, 4, 4, 4, 4, ... Number Pattern & Puzzle NMTC PRMO

Area of the shaded region in a unit circle | Difficult problem easy PRMO NMTC SSB CGL IBPS Bank PO

Area of the shaded region in a unit circle | Difficult problem easy PRMO NMTC SSB CGL IBPS Bank PO

Finding Values of sin15, cos15, cosec 15, sec15, tan15 and cot 15

Finding Values of sin15, cos15, cosec 15, sec15, tan15 and cot 15

Find Angle | Solve the problem using Congruency | Difficult Problem | PRMO NMTC CGL SSB IBPS Bank PO

Find Angle | Solve the problem using Congruency | Difficult Problem | PRMO NMTC CGL SSB IBPS Bank PO

Speed and Distance |Two boats moving in opposite direction, meet twice, find the width of the river

Speed and Distance |Two boats moving in opposite direction, meet twice, find the width of the river

Area of the shaded region | SSB CGL PRMO NMTC Coordinate geometry | Difficult problem easy solution

Area of the shaded region | SSB CGL PRMO NMTC Coordinate geometry | Difficult problem easy solution

Difficult problem Easy Solution | NMTC PRMO SSB CGL IBPS | Geometry with cut and paste

Difficult problem Easy Solution | NMTC PRMO SSB CGL IBPS | Geometry with cut and paste

Find Angle inside a circle | IBPS SSB PSU PRMO NMTC | A difficult problem with Simple Solution | SAS

Find Angle inside a circle | IBPS SSB PSU PRMO NMTC | A difficult problem with Simple Solution | SAS

NMTC 2019 a quadratic expression with another quadratic expression as an exponent Difficult & Tricky

NMTC 2019 a quadratic expression with another quadratic expression as an exponent Difficult & Tricky

Hemisphere inside a pyramid | Most people make mistake in drawing this SSC CGL IBPS Competetive exam

Hemisphere inside a pyramid | Most people make mistake in drawing this SSC CGL IBPS Competetive exam

Geometry | A difficult problem to solve | Area of Shaded region | SSC | IBPS | Competetive exams

Geometry | A difficult problem to solve | Area of Shaded region | SSC | IBPS | Competetive exams

Find Theta. A difficult problem with simple solution | IBPS | SSC | Competition

Find Theta. A difficult problem with simple solution | IBPS | SSC | Competition

How to draw Length in square root | irrational length | How to measure sqrt(x)

How to draw Length in square root | irrational length | How to measure sqrt(x)

A difficult problem with easy solution | problem on intersecting chords

A difficult problem with easy solution | problem on intersecting chords

Sum of n Triangular numbers | Derivation | Formula | PRMO RMO INMO IIT JEE NTSE NMTC

Sum of n Triangular numbers | Derivation | Formula | PRMO RMO INMO IIT JEE NTSE NMTC

Sum of squares of odd Numbers 1^2 + 3^2+ 5^2 + ... + (2n -1)^2 Derivation | Formula | PRMO RMO IIT

Sum of squares of odd Numbers 1^2 + 3^2+ 5^2 + ... + (2n -1)^2 Derivation | Formula | PRMO RMO IIT

Derivation | Formula | Sum of first n squares or square numbers 1^2 + 2^2 + 3^2 + 4^2 +...n^2

Derivation | Formula | Sum of first n squares or square numbers 1^2 + 2^2 + 3^2 + 4^2 +...n^2

Proving equations in Trigonometry (sec A - tan A) /(sec A + tan A) = 1 - 2sec A tan A + 2 tan^2 A

Proving equations in Trigonometry (sec A - tan A) /(sec A + tan A) = 1 - 2sec A tan A + 2 tan^2 A

Sum of angles of a 7 pointed star | Mental ability | IBPS SSC

Sum of angles of a 7 pointed star | Mental ability | IBPS SSC

Area of the shaded region | Tricky Area problem | Difficult |

Area of the shaded region | Tricky Area problem | Difficult |

x^2 + y^2 = 74 and xy = 35 find x + y and x - y, 2x + 3y = 14 and xy = 8 find 4x^2 + 9y^2

x^2 + y^2 = 74 and xy = 35 find x + y and x - y, 2x + 3y = 14 and xy = 8 find 4x^2 + 9y^2

x+y = 15, xy = 54 find x^2 - y^2, Basic Algebra manipulation. CBSE Grade 8 Question by viewer

x+y = 15, xy = 54 find x^2 - y^2, Basic Algebra manipulation. CBSE Grade 8 Question by viewer

Trick Difficult problem Perimeter of an equilateral triangle inscribed in a circle | Trigonometry

Trick Difficult problem Perimeter of an equilateral triangle inscribed in a circle | Trigonometry

Difficult mensuration problem with simple logical solution | Find area of AOC

Difficult mensuration problem with simple logical solution | Find area of AOC

Difficult puzzle easy solution | Angles inside a circle | Cyclic Quadrilateral | Job | Career

Difficult puzzle easy solution | Angles inside a circle | Cyclic Quadrilateral | Job | Career

Solution | Day 15 | Area of chaded region | Job Career | Bank PO | SSC | Mensuration | Fun Math

Solution | Day 15 | Area of chaded region | Job Career | Bank PO | SSC | Mensuration | Fun Math

15 days puzzle challenge | Day 15

15 days puzzle challenge | Day 15

Difficult puzzle easy solution | intersecting circles | Fun Math | Job | Career | Bank PO

Difficult puzzle easy solution | intersecting circles | Fun Math | Job | Career | Bank PO

15 days puzzle challenge | Day 14 | Cyclic quadrilateral | Job | Career

15 days puzzle challenge | Day 14 | Cyclic quadrilateral | Job | Career

Solution Day 13 | Mental ability | Calendar based problems | Fun Math | Jobs | Career

Solution Day 13 | Mental ability | Calendar based problems | Fun Math | Jobs | Career

15 days puzzle challenge Day 13 Calendar based problems

15 days puzzle challenge Day 13 Calendar based problems

Measuring cups puzzle | Measure 20 ml using 40 and 70 ml cups| Logical reasoning | Mental ability

Measuring cups puzzle | Measure 20 ml using 40 and 70 ml cups| Logical reasoning | Mental ability

Find the fake coin out of 15 | How to find fake coin | Mental ability | Logical reasoning

Find the fake coin out of 15 | How to find fake coin | Mental ability | Logical reasoning

15 days puzzle challenge | Day 12 | Mental ability | Logical reasoning | Fun Math

15 days puzzle challenge | Day 12 | Mental ability | Logical reasoning | Fun Math

Difficult problem with easy solution | Area of shaded region | Tricky wicked problem | Mensuration

Difficult problem with easy solution | Area of shaded region | Tricky wicked problem | Mensuration

Solution day 11 | Mensuration | Tricky hard | Solved example | Mensuration

Solution day 11 | Mensuration | Tricky hard | Solved example | Mensuration

15 days Pyzzle challenge | Day 11 | Mental ability | Mensuration

15 days Pyzzle challenge | Day 11 | Mental ability | Mensuration

Solutions | Day 10 | Find your way | Count Number of ways | Mental Ability | Job | Career

Solutions | Day 10 | Find your way | Count Number of ways | Mental Ability | Job | Career

15 days puzzle challenge | Day 10 | Count no of ways | Mental Ability | Tricky

15 days puzzle challenge | Day 10 | Count no of ways | Mental Ability | Tricky

Solutions Day 9 | Mensuration | Area of shaded region | Mental Ability | Jobs | Career

Solutions Day 9 | Mensuration | Area of shaded region | Mental Ability | Jobs | Career

15 days puzzle challenge | Day 9| Fun Math | Mental Ability | Competetive exams

15 days puzzle challenge | Day 9| Fun Math | Mental Ability | Competetive exams

Solution Day 8 | Recurring surds | Infinite sequences | Fast calculation | Trick

Solution Day 8 | Recurring surds | Infinite sequences | Fast calculation | Trick

15 days puzzle challenge | Day 8 | Recurring surds | Mental ability | quick math

15 days puzzle challenge | Day 8 | Recurring surds | Mental ability | quick math

Solution | Day 7 | Mental Ability | Tricky problems | Wicked | Mental ability | Common sense

Solution | Day 7 | Mental Ability | Tricky problems | Wicked | Mental ability | Common sense

15 day puzzle challenge | Day 7 | Tricky math | Mental ability | wicked puzzles | Bank PO | IBPS

15 day puzzle challenge | Day 7 | Tricky math | Mental ability | wicked puzzles | Bank PO | IBPS

Solution | Day 6 | Puzzles | Mental Ability | Tricky math | Fun Math | Brain Twisters

Solution | Day 6 | Puzzles | Mental Ability | Tricky math | Fun Math | Brain Twisters

15 days puzzle challenge | Day 6 | Puzzle set |

15 days puzzle challenge | Day 6 | Puzzle set |

Solutions | Day 5 | Puzzles | Number Pattern | Mental ability

Solutions | Day 5 | Puzzles | Number Pattern | Mental ability

15 days Puzzle challenge | Day 5 | Mental Ability | Logical Reasonong

15 days Puzzle challenge | Day 5 | Mental Ability | Logical Reasonong

Solutions for Day 4 | Number Pattern and Sequence | Mental Ability | Bank PO | IBPS

Solutions for Day 4 | Number Pattern and Sequence | Mental Ability | Bank PO | IBPS

15 days puzzle challenge | Day 4 | Number pattern | Fun with numbers Mental ability

15 days puzzle challenge | Day 4 | Number pattern | Fun with numbers Mental ability

Solution to Puzzle3 of Day 3 | Area of shaded region | Mental ability | Area | Mensuration

Solution to Puzzle3 of Day 3 | Area of shaded region | Mental ability | Area | Mensuration

Solution to Puzzle 2 of Day 3 | Area of complicated figure | Mental Ability | Mensuration

Solution to Puzzle 2 of Day 3 | Area of complicated figure | Mental Ability | Mensuration

Solution to Puzzle 1 of Day 3 | Finding Area of shaded region | Mental ability | Mensuration

Solution to Puzzle 1 of Day 3 | Finding Area of shaded region | Mental ability | Mensuration

15 days Puzzle challenge | Day 3| Mensuration | Mental ability | Fun Math

15 days Puzzle challenge | Day 3| Mensuration | Mental ability | Fun Math

Difficult puzzle easy solution | use 1 to 9 only once | without repeating numbers | Mental ability

Difficult puzzle easy solution | use 1 to 9 only once | without repeating numbers | Mental ability

15 days Puzzle challenge | Day 2| Number patterns | Mental ability | Fun Math

15 days Puzzle challenge | Day 2| Number patterns | Mental ability | Fun Math

Solutions to puzzles of day 1 | Number Pattern | Series | Sequence | Mental ability

Solutions to puzzles of day 1 | Number Pattern | Series | Sequence | Mental ability

15 days Puzzle challenge | Day 1| Number patterns | Mental ability | Fun Math

15 days Puzzle challenge | Day 1| Number patterns | Mental ability | Fun Math

Interesting and HARD Viral math puzzle | Mental Ability | Mental Math | Competetive Exams

Interesting and HARD Viral math puzzle | Mental Ability | Mental Math | Competetive Exams

Work Time solved example | Solved problem | IBPS | Bank PO

Work Time solved example | Solved problem | IBPS | Bank PO

12 men take 6 hrs, after 1 hr 8 more men join. Find time to finish. Bank PO IBPS Time and work

12 men take 6 hrs, after 1 hr 8 more men join. Find time to finish. Bank PO IBPS Time and work

Puzzle | Solution to a math problem, which went viral on WhatsApp | Fun Math

Puzzle | Solution to a math problem, which went viral on WhatsApp | Fun Math

Recurring Square root | Hard problem with simple solution | Mental ability | IBPS | Bank PO |

Recurring Square root | Hard problem with simple solution | Mental ability | IBPS | Bank PO |

HARD problem & Simple Solution | surds | Squareroot of 100x101x102x103+1 | Mental ability | IAS

HARD problem & Simple Solution | surds | Squareroot of 100x101x102x103+1 | Mental ability | IAS

Logic behind the procedure of drawing incircle of a triangle |Practical Geometry

Logic behind the procedure of drawing incircle of a triangle |Practical Geometry

How to draw Incircle of a triangle | Practical Geometry

How to draw Incircle of a triangle | Practical Geometry

Smallest Number divide by 10,13,17 different remainders 3,11,15 respectively IBPS | Bank PO LCM HCF

Smallest Number divide by 10,13,17 different remainders 3,11,15 respectively IBPS | Bank PO LCM HCF

Logic behind the procedure to draw circum circle | Practical Geometry

Logic behind the procedure to draw circum circle | Practical Geometry

How to draw circumcircle of a triangle | Practical Geometry

How to draw circumcircle of a triangle | Practical Geometry

How to make Angles using Compass and ruler and Why it works | Practical Geometry

How to make Angles using Compass and ruler and Why it works | Practical Geometry

Solve (sec^2 (10) - 1)(sec 20 + 1)(sec 40 + 1)(sec 80 + 1)

Solve (sec^2 (10) - 1)(sec 20 + 1)(sec 40 + 1)(sec 80 + 1)

Prove [(1 + SinA - Cos A) / (1 + Sin A + Cos A)]^2 = (1- CosA)/(1+ CosA)

Prove [(1 + SinA - Cos A) / (1 + Sin A + Cos A)]^2 = (1- CosA)/(1+ CosA)

How to draw Angle bisector and the logic behind the procedure Practical Geometry

How to draw Angle bisector and the logic behind the procedure Practical Geometry

How to Divide a line in the given ratio | Divide a line in the ratio of 3 : 4 | Practical Geometry

How to Divide a line in the given ratio | Divide a line in the ratio of 3 : 4 | Practical Geometry

How to divide a line into given number of equal parts Practical Geometry | Construction

How to divide a line into given number of equal parts Practical Geometry | Construction

How to draw a perpendicular on a point of the line | Construction | CBSE | ICSE | Practical Geometry

How to draw a perpendicular on a point of the line | Construction | CBSE | ICSE | Practical Geometry

How to draw a perpendicular from a given point to a given line | Geometry construction

How to draw a perpendicular from a given point to a given line | Geometry construction

How to draw Perpendicular bisector | Method | Logic behind the method its Properties

How to draw Perpendicular bisector | Method | Logic behind the method its Properties

Trigonometry | Sin^6A minus cos^6A | Solved Problem

Trigonometry | Sin^6A minus cos^6A | Solved Problem

Square root of an Algebraic Expression | Division Method | Algebra |

Square root of an Algebraic Expression | Division Method | Algebra |

squareroot of 4.2025

squareroot of 4.2025

Shri Dharacharya | Sridhar Achaya Formula to find roots of a quadratic equation | Derivation

Shri Dharacharya | Sridhar Achaya Formula to find roots of a quadratic equation | Derivation

Finding roots of a Quadratic Equation and the logic behind the formula of finding roots of | Part 2

Finding roots of a Quadratic Equation and the logic behind the formula of finding roots of | Part 2

Roots of quadratic euqations using factorisation | Solving Quadratic equation | Part -1

Roots of quadratic euqations using factorisation | Solving Quadratic equation | Part -1

Logic behind the General or Universal divisibility rule | Pank PO | IBPS |

Logic behind the General or Universal divisibility rule | Pank PO | IBPS |

General or Universal divisibility rule | One Rule for all divisors | Pank PO | IBPS |

General or Universal divisibility rule | One Rule for all divisors | Pank PO | IBPS |

BODMAS | PEMDAS | Plus minus powers brackets division multiplication correct sequence | Bank PO IBPS

BODMAS | PEMDAS | Plus minus powers brackets division multiplication correct sequence | Bank PO IBPS

Smallest Number divided by 11,13,15 leaves remainder 1,2,3 | IBPS | Bank PO | SSC

Smallest Number divided by 11,13,15 leaves remainder 1,2,3 | IBPS | Bank PO | SSC

LCM problem where remainder is not same and difference of remainder and divisor is also not same

LCM problem where remainder is not same and difference of remainder and divisor is also not same

LCM and HCF or GCD of Fractional or rational Numbers | IBPS | Bank PO

LCM and HCF or GCD of Fractional or rational Numbers | IBPS | Bank PO

How to calculate Average Speed ? IBPs | Bank PO | SSC

How to calculate Average Speed ? IBPs | Bank PO | SSC

Find average of A, B and C| find number of items | Bank PO | IBPS | SSC

Find average of A, B and C| find number of items | Bank PO | IBPS | SSC

Concepts of Average| finding values when average is given| 2 Solved questions | IBPS | Bank PO |SSC

Concepts of Average| finding values when average is given| 2 Solved questions | IBPS | Bank PO |SSC

Divisibility rule of 19 second | check if a number is divisible by 19 | Bank PO | IBPS | SSC

Divisibility rule of 19 second | check if a number is divisible by 19 | Bank PO | IBPS | SSC

Divisibility Rule of 17 | Check divisibility by 17 | Bank PO | IBPS | SSC

Divisibility Rule of 17 | Check divisibility by 17 | Bank PO | IBPS | SSC

Divisibility Rule of 13 (Second Rule) : Bank PO | IBPS | SSC

Divisibility Rule of 13 (Second Rule) : Bank PO | IBPS | SSC

Solved Question (Difficulty Medium) finding distance between midpoints of two chords | IBPS | SSC

Solved Question (Difficulty Medium) finding distance between midpoints of two chords | IBPS | SSC

Solved questions (2)( shortcut) on chord and perpendicular on a chord | IBPS | Bank PO | SSC

Solved questions (2)( shortcut) on chord and perpendicular on a chord | IBPS | Bank PO | SSC

Derivation or Proof of Heron's formula : Find area of a triangle with given sides | Logic Behind

Derivation or Proof of Heron's formula : Find area of a triangle with given sides | Logic Behind

Perpendicular from the centre bisects the chord | proof |IBPS | Bank PO | SSC

Perpendicular from the centre bisects the chord | proof |IBPS | Bank PO | SSC

Two equal chords subtend equal angles at the centre | Proof | IBPS | Bank PO | SSC

Two equal chords subtend equal angles at the centre | Proof | IBPS | Bank PO | SSC

What is sector and segment of a circle and hoe to tind their Area

What is sector and segment of a circle and hoe to tind their Area

Mathssmart Hindi | Our New channel for viewers who like to learn Mathematics in Hindi

Mathssmart Hindi | Our New channel for viewers who like to learn Mathematics in Hindi

Circle, Radius, Diameter, Chord, Circumference, Perimeter, Area : Concepts and Derivations

Circle, Radius, Diameter, Chord, Circumference, Perimeter, Area : Concepts and Derivations

Area of Rectangle, Square, Parallelogram, Triangle, Trapezoid, Rhombus and Kite : Derivation | Proof

Area of Rectangle, Square, Parallelogram, Triangle, Trapezoid, Rhombus and Kite : Derivation | Proof

AP | If a,b,c are in AP, then prove that a(b+c)/bc, b(c+a)/ca, c(a+b)/ab are also in AP

AP | If a,b,c are in AP, then prove that a(b+c)/bc, b(c+a)/ca, c(a+b)/ab are also in AP

Why division method of square root works | Logic behind the Euclid's algorithm of square root

Why division method of square root works | Logic behind the Euclid's algorithm of square root

Different types of quadrilaterals and their properties : Bank PO : IBPS

Different types of quadrilaterals and their properties : Bank PO : IBPS

solve work and time problem in less than a minute without formula | Bank PO : SSC : IBPS

solve work and time problem in less than a minute without formula | Bank PO : SSC : IBPS

Easy method : work and time : workers leaving and joining the work inbetween : Bank PO : SSC : IBPS

Easy method : work and time : workers leaving and joining the work inbetween : Bank PO : SSC : IBPS

Componendo and Dividendo : Ratio and proportions : Solved example : Question : IBPS : SSC : Bank Po

Componendo and Dividendo : Ratio and proportions : Solved example : Question : IBPS : SSC : Bank Po

Geometrical explanation of (a+b+c)^2 | Algebraic identity | Proof | Derivation | Math project

Geometrical explanation of (a+b+c)^2 | Algebraic identity | Proof | Derivation | Math project

Solved Question using ratio and proportion | BANK PO | IBPS | Arithmetic

Solved Question using ratio and proportion | BANK PO | IBPS | Arithmetic

Continued proportion | a:b:c and a:b = b:c

Continued proportion | a:b:c and a:b = b:c

Componendo and dividendo : properties of proportion | Arithmetic | Bank Po IBPS

Componendo and dividendo : properties of proportion | Arithmetic | Bank Po IBPS

MathsSmart Live Stream

MathsSmart Live Stream

Proportions an Introduction

Proportions an Introduction

Divide 360 in the ratio 4:5 and more

Divide 360 in the ratio 4:5 and more

Properties of ratios : Ratio and proportions

Properties of ratios : Ratio and proportions

Types of ratios : duplicate, subduplicate, triplicate subtriplicate, inverse, compound

Types of ratios : duplicate, subduplicate, triplicate subtriplicate, inverse, compound

Introduction to ratios : Ratios and proportions

Introduction to ratios : Ratios and proportions

Calculus: Limits at inifinity problems and solutions

Calculus: Limits at inifinity problems and solutions

Calculus: Finding limits when x tends to infinity

Calculus: Finding limits when x tends to infinity

Calculus: problems or questions on limits by factorisation

Calculus: problems or questions on limits by factorisation

Calculus - finding limit by factorisation

Calculus - finding limit by factorisation

Introduction to limits

Introduction to limits

Proof to (x + a) (x + b) = x^2 + (a+b)x + ab

Proof to (x + a) (x + b) = x^2 + (a+b)x + ab

Trigonometry : proof : cos (A + B) = cos A cos B - sin A sin B : Derivation

Trigonometry : proof : cos (A + B) = cos A cos B - sin A sin B : Derivation

Trigonometry : Proof of sin (A + B) = sin A cos B + cos A sin B

Trigonometry : Proof of sin (A + B) = sin A cos B + cos A sin B

Trigonometry : what is positive and negative angle

Trigonometry : what is positive and negative angle

Solved example : Proving Equation : using 1 + cot^2 A = cosec^2 A : Trigonometry

Solved example : Proving Equation : using 1 + cot^2 A = cosec^2 A : Trigonometry

Trigonometry : Proving equations : using 1 + tan^2 A = sec^2 A : Solved example

Trigonometry : Proving equations : using 1 + tan^2 A = sec^2 A : Solved example

Solved example in Trigonometry : proving Equations : medium difficulty

Solved example in Trigonometry : proving Equations : medium difficulty

Solved Example : Trigonometry : Prove (1 + tan^2 A) / ( 1 + cot^2 A) = sin^2 A / cos^2 A

Solved Example : Trigonometry : Prove (1 + tan^2 A) / ( 1 + cot^2 A) = sin^2 A / cos^2 A