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Problem link on LeetCode: [ Ссылка ]
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Algorithm explained:
One character could have at most two neighbors, so we only need to toggle between three candidate characters before we could find a valid one that is not a consecutive repeating character with its preceding and succeeding characters.
// TOOLS THAT I USE:
○ Memory Foam Set Keyboard Wrist Rest Pad - [ Ссылка ]
○ Electric Height Adjustable Standing Desk - [ Ссылка ]
○ Apple Magic Keyboard (Wireless, Rechargable) - [ Ссылка ]
○ Apple Magic Trackpad 2 (Wireless, Rechargable) - [ Ссылка ]
○ Apple MacBook Pro - [ Ссылка ]
○ All-In One Printer - [ Ссылка ]
○ Apple AirPods Pro - [ Ссылка ]
○ My new favorite Apple Watch - [ Ссылка ]
// MY FAVORITE BOOKS:
○ Introduction to Algorithms - [ Ссылка ]
○ Designing Data-Intensive Applications - [ Ссылка ]
○ Head First Java - [ Ссылка ]
○ Design Patterns - [ Ссылка ]
Follow me on Github for more LeetCode solutions: [ Ссылка ]
Support me on Patreon: [ Ссылка ]
My ENTIRE Programming Equipment and Computer Science Bookshelf:
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Your comments/thoughts/questions/advice will be greatly appreciated!
#LeetCode #softwareengineering #interview #algorithms #coding #interview #SDE #SWE #SiliconValley #programming #datastructures
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