Question 17) The first term 𝒙_𝟏 of a sequence is 2014. Each subsequent term of the sequence is defined in terms of the previous term. The iterative formula is
𝒙_(𝒏+𝟏)= ((√𝟐+𝟏) 𝒙_𝒏−𝟏)/((√𝟐+𝟏)+𝒙_𝒏 )
Find the 2015th term 𝒙_𝟐𝟎𝟏𝟓 .

This question was asked in British Mathematical Olympiad (BMO) Round 2 in 2015

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