This video describes the principle behind fluorescence spectra and how they can be used to determine properties of a fluorescent molecule. Learn more: [ Ссылка ]

AUDIO TRANSCRIPT

The basic fluorescence properties of a fluorophore—excitation and emission—are often presented in the form of line graphs. These curves describe the likelihood that excitation and emission will occur as a function of wavelength and provide important information about the expected behavior of the irradiated fluorophore. Understanding the information is an important step in understanding the phenomenon of fluorescence.

A fluorophore is excited most efficiently by light of a particular wavelength. This wavelength is the excitation maximum for the fluorophore.

Light with a wavelength near the excitation maximum can also cause excitation, as shown by the shaded areas, but it does so less efficiently.

Fluorescence emission behaves in a similar way: the fluorescence output of a fluorophore is most likely to occur at a particular wavelength. This wavelength is the emission maximum for that fluorophore.

The excited fluorophore can also emit light at wavelengths near the emission maximum, as shown. However, this light will be less intense.

It is important to remember that although illumination at the excitation maximum of the fluorophore produces the greatest fluorescence output, illumination at lower or higher wavelengths affects only the intensity of the emitted light—the range and overall shape of the emission profile are unchanged.

As this animation shows, less efficient excitation can occur at wavelengths near the excitation maximum; however, the intensity of the emitted fluorescence is reduced.
Notice that the emission maximum for the fluorophore is always at a longer wavelength—that is, has lower energy—than the excitation maximum. This difference between the excitation and emission maxima is called the Stokes shift. The magnitude of the Stokes shift is determined by the electronic structure of the fluorophore, and is a characteristic of the fluorophore molecule. So, what causes this energy loss?

The Stokes shift is due to the fact that some of the energy of the excited fluorophore is lost through molecular vibrations that occur during the brief lifetime of the molecule's excited state. This energy is dissipated as heat to surrounding solvent molecules as they collide with the excited fluorophore.

In summary, the excitation and emission spectra of a fluorophore contain important practical information about what wavelengths of light we need to supply and detect, in order to use that fluorophore effectively. In addition, excitation and emission spectra must be examined carefully, when choosing two or more fluorophores to use simultaneously in an experiment, so that the fluorophores can be excited in a manner that will generate distinct emissions.

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