A first order reaction has integrated rate law
[A] = [A]0 e^(-kt)
which is the same as ln [A] = -kt + ln [A]0
Which means a graph of ln [A] vs time will give a line with slope -k and a y-intercept of ln [A]0.
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A first order reaction has integrated rate law
[A] = [A]0 e^(-kt)
which is the same as ln [A] = -kt + ln [A]0
Which means a graph of ln [A] vs time will give a line with slope -k and a y-intercept of ln [A]0.
Check me out: [ Ссылка ]